Algebra 2 HW for 9/30

OK, for those of you who didn't copy it down, here's the system of equations I assigned: 

 x +  2y +  3z  =    6
3x +  7y + 11z  =   22
5x + 12y + 48z  =  125


First try multiplying the first equation by -3 and adding it to the second. Then multiply it by -5 and add it to the third. Cancel out the y's in the third equation by multiplying the new second one. That will give you the z, and you can multiply it and cancel the second equation's z term. After you have the y in the second one, you can use it and the z from the third one to cancel out the y and z in the first equation.


See you Monday!